LeetCode之Number Complement

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chenyu 发表于 2021/07/27 00:31:56 2021/07/27
【摘要】 1、题目   Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fi...

1、题目

 

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.

Note:

  1. The given integer is guaranteed to fit within the range of a 32-bit signed integer.
  2. You could assume no leading zero bit in the integer’s binary representation.

Example 1:


  
  1. Input: 5
  2. Output: 2
  3. Explanation: The binary representation of 5 is 101 (no leading zero bits), and its complement is 010. So you need to output 2.

Example 2:


  
  1. Input: 1
  2. Output: 0
  3. Explanation: The binary representation of 1 is 1 (no leading zero bits), and its complement is 0. So you need to output 0.

 

 

 

2、代码实现

 

 


  
  1. public class Solution {
  2. public int findComplement(int num) {
  3. if (num <= 0)
  4. return 0;
  5. String result = "";
  6. while (num > 0) {
  7. result += num % 2;
  8. num = num / 2;
  9. }
  10. int length = result.length();
  11. int lastResult = 0;
  12. for (int i = 0; i < length - 1; ++i) {
  13. if (result.charAt(i) == '0') {
  14. int temp = (int) Math.pow(2, i);
  15. lastResult += temp;
  16. }
  17. }
  18. return lastResult;
  19. }
  20. }

 

 

 

 

 

 

文章来源: chenyu.blog.csdn.net,作者:chen.yu,版权归原作者所有,如需转载,请联系作者。

原文链接:chenyu.blog.csdn.net/article/details/69643973

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