CosineWarmup理论介绍与代码实战

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李长安 发表于 2023/03/18 12:39:11 2023/03/18
【摘要】 CosineWarmup是一种非常实用的训练策略,本次教程将带领大家实现该训练策略。教程将从理论和代码实战两个方面进行。

CosineWarmup理论介绍与代码实战

  CosineWarmup是一种非常实用的训练策略,本次教程将带领大家实现该训练策略。教程将从理论和代码实战两个方面进行。

  在代码实战部分,模型采用LeNet-5模型进行测试,数据采用Cifar10数据集作为基准数据,

  Warmup最早出现于这篇文章中:Accurate, Large Minibatch SGD:Training ImageNet in 1 Hour,warmup类似于跑步中的热身,在刚刚开始训练的时候进行热身,使得网络逐渐熟悉数据的分布,随着训练的进行学习率慢慢变大,到了指定的轮数,再使用初始学习率进行训练。

  consine learning rate则来自于这篇文章Bag of Tricks for Image Classification with Convolutional Neural Networks,通过余弦函数对学习率进行调整

  一般情况下,只在前五个Epoch中使用Warmup,并且通常情况下,把warm up和consine learning rate一起使用会达到更好的效果。

  • Warmup

  Warmup是在ResNet论文中提到的一种学习率预热的方法,它在训练开始的时候先选择使用一个较小的学习率,训练了一些epoches或者steps(比如4个epoches,10000steps),再修改为预先设置的学习来进行训练。由于刚开始训练时,模型的权重(weights)是随机初始化的,此时若选择一个较大的学习率,可能带来模型的不稳定(振荡),选择Warmup预热学习率的方式,可以使得开始训练的几个epoches或者一些steps内学习率较小,在预热的小学习率下,模型可以慢慢趋于稳定,等模型相对稳定后再选择预先设置的学习率进行训练,使得模型收敛速度变得更快,模型效果更佳。

  • 余弦退火策略

  当我们使用梯度下降算法来优化目标函数的时候,当越来越接近Loss值的全局最小值时,学习率应该变得更小来使得模型尽可能接近这一点,而余弦退火(Cosine annealing)可以通过余弦函数来降低学习率。余弦函数中随着x的增加余弦值首先缓慢下降,然后加速下降,再次缓慢下降。这种下降模式能和学习率配合,以一种十分有效的计算方式来产生很好的效果。

  • 带Warmup的余弦退火策略

  • 单个周期余弦退火衰减图形

  以单个周期余弦退火衰减为例,介绍带Warmup的余弦退火策略,如下图所示,学习率首先缓慢升高,达到设定的最高值之后,通过余弦函数进行衰减调整。但是通常面对大数据集的时候,学习率可能会多次重复上述调整策略。

代码实现

from paddle.optimizer.lr import LinearWarmup

from paddle.optimizer.lr import CosineAnnealingDecay


class Cosine(CosineAnnealingDecay):
    """
    Cosine learning rate decay
    lr = 0.05 * (math.cos(epoch * (math.pi / epochs)) + 1)

    Args:
        lr(float): initial learning rate
        step_each_epoch(int): steps each epoch
        epochs(int): total training epochs
    """

    def __init__(self, lr, step_each_epoch, epochs, **kwargs):
        super(Cosine, self).__init__(
            learning_rate=lr,
            T_max=step_each_epoch * epochs, )

        self.update_specified = False

class CosineWarmup(LinearWarmup):
    """
    Cosine learning rate decay with warmup
    [0, warmup_epoch): linear warmup
    [warmup_epoch, epochs): cosine decay

    Args:
        lr(float): initial learning rate
        step_each_epoch(int): steps each epoch
        epochs(int): total training epochs
        warmup_epoch(int): epoch num of warmup
    """

    def __init__(self, lr, step_each_epoch, epochs, warmup_epoch=5, **kwargs):
        assert epochs > warmup_epoch, "total epoch({}) should be larger than warmup_epoch({}) in CosineWarmup.".format(
            epochs, warmup_epoch)
        warmup_step = warmup_epoch * step_each_epoch
        start_lr = 0.0
        end_lr = lr
        lr_sch = Cosine(lr, step_each_epoch, epochs - warmup_epoch)

        super(CosineWarmup, self).__init__(
            learning_rate=lr_sch,
            warmup_steps=warmup_step,
            start_lr=start_lr,
            end_lr=end_lr)

        self.update_specified = False

实战

import paddle
import paddle.nn.functional as F
from paddle.vision.transforms import ToTensor
from paddle import fluid
import paddle.nn as nn


print(paddle.__version__)
2.0.2
transform = ToTensor()
cifar10_train = paddle.vision.datasets.Cifar10(mode='train',
                                               transform=transform)
cifar10_test = paddle.vision.datasets.Cifar10(mode='test',
                                              transform=transform)

# 构建训练集数据加载器
train_loader = paddle.io.DataLoader(cifar10_train, batch_size=64, shuffle=True)

# 构建测试集数据加载器
test_loader = paddle.io.DataLoader(cifar10_test, batch_size=64, shuffle=True)
Cache file /home/aistudio/.cache/paddle/dataset/cifar/cifar-10-python.tar.gz not found, downloading https://dataset.bj.bcebos.com/cifar/cifar-10-python.tar.gz 
Begin to download

Download finished
class MyNet(paddle.nn.Layer):
    def __init__(self, num_classes=10):
        super(MyNet, self).__init__()

        self.conv1 = paddle.nn.Conv2D(in_channels=3, out_channels=32, kernel_size=(3, 3), stride=1, padding = 1)
        # self.pool1 = paddle.nn.MaxPool2D(kernel_size=2, stride=2)
        self.conv2 = paddle.nn.Conv2D(in_channels=32, out_channels=64, kernel_size=(3,3),  stride=2, padding = 0)
        # self.pool2 = paddle.nn.MaxPool2D(kernel_size=2, stride=2)

        self.conv3 = paddle.nn.Conv2D(in_channels=64, out_channels=64, kernel_size=(3,3), stride=2, padding = 0)
        # self.DropBlock =  DropBlock(block_size=5, keep_prob=0.9, name='le')
        self.conv4 = paddle.nn.Conv2D(in_channels=64, out_channels=64, kernel_size=(3,3), stride=2, padding = 1)

        self.flatten = paddle.nn.Flatten()

        self.linear1 = paddle.nn.Linear(in_features=1024, out_features=64)
        self.linear2 = paddle.nn.Linear(in_features=64, out_features=num_classes)

    def forward(self, x):
        x = self.conv1(x)
        x = F.relu(x)
        # x = self.pool1(x)
        # print(x.shape)
        x = self.conv2(x)
        x = F.relu(x)
        # x = self.pool2(x)
        # print(x.shape)

        x = self.conv3(x)
        x = F.relu(x)
        # print(x.shape)
        
        # x = self.DropBlock(x)
        x = self.conv4(x)
        x = F.relu(x)
        # print(x.shape)

        x = self.flatten(x)
        x = self.linear1(x)
        x = F.relu(x)
        x = self.linear2(x)
        return x

# 可视化模型

cnn2 = MyNet()

model2 = paddle.Model(cnn2)

model2.summary((64, 3, 32, 32))
---------------------------------------------------------------------------
 Layer (type)       Input Shape          Output Shape         Param #    
===========================================================================
   Conv2D-1      [[64, 3, 32, 32]]     [64, 32, 32, 32]         896      
   Conv2D-2      [[64, 32, 32, 32]]    [64, 64, 15, 15]       18,496     
   Conv2D-3      [[64, 64, 15, 15]]     [64, 64, 7, 7]        36,928     
   Conv2D-4       [[64, 64, 7, 7]]      [64, 64, 4, 4]        36,928     
   Flatten-1      [[64, 64, 4, 4]]        [64, 1024]             0       
   Linear-1         [[64, 1024]]           [64, 64]           65,600     
   Linear-2          [[64, 64]]            [64, 10]             650      
===========================================================================
Total params: 159,498
Trainable params: 159,498
Non-trainable params: 0
---------------------------------------------------------------------------
Input size (MB): 0.75
Forward/backward pass size (MB): 25.60
Params size (MB): 0.61
Estimated Total Size (MB): 26.96
---------------------------------------------------------------------------






{'total_params': 159498, 'trainable_params': 159498}
# 配置模型

from paddle.metric import Accuracy


scheduler = CosineWarmup(
        lr=0.5, step_each_epoch=100, epochs=8, warmup_steps=20, start_lr=0, end_lr=0.5, verbose=True)
optim = paddle.optimizer.SGD(learning_rate=scheduler, parameters=model2.parameters())

model2.prepare(
    optim,
    paddle.nn.CrossEntropyLoss(),
    Accuracy()
    )

# 模型训练与评估
model2.fit(train_loader,
        test_loader,
        epochs=10,
        verbose=1,
        )
The loss value printed in the log is the current step, and the metric is the average value of previous step.
Epoch 1/3


/opt/conda/envs/python35-paddle120-env/lib/python3.7/site-packages/paddle/fluid/layers/utils.py:77: DeprecationWarning: Using or importing the ABCs from 'collections' instead of from 'collections.abc' is deprecated, and in 3.8 it will stop working
  return (isinstance(seq, collections.Sequence) and


step 782/782 [==============================] - loss: 1.9828 - acc: 0.2280 - 106ms/step         
Eval begin...
The loss value printed in the log is the current batch, and the metric is the average value of previous step.
step 157/157 [==============================] - loss: 1.5398 - acc: 0.3646 - 35ms/step        
Eval samples: 10000
Epoch 2/3
step 782/782 [==============================] - loss: 1.7682 - acc: 0.3633 - 106ms/step         
Eval begin...
The loss value printed in the log is the current batch, and the metric is the average value of previous step.
step 157/157 [==============================] - loss: 1.7934 - acc: 0.3867 - 34ms/step        
Eval samples: 10000
Epoch 3/3
step 782/782 [==============================] - loss: 1.3394 - acc: 0.4226 - 105ms/step         
Eval begin...
The loss value printed in the log is the current batch, and the metric is the average value of previous step.
step 157/157 [==============================] - loss: 1.4539 - acc: 0.3438 - 35ms/step        
Eval samples: 10000

总结

  之前一直提到这个CosineWarmup,但是一直没有实现过,这次也算是填了一个很早之前就挖的坑。同样,这里也不再设置对比实验,因为这个东西确实很管用。小模型和小数据集可能不太能够体现该训练策略的有效性。大家如果有兴趣可以使用更大的模型、更大的数据集测试一下。

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