Bear and Big Brother

举报
辰chen 发表于 2022/06/15 01:01:37 2022/06/15
【摘要】 文章目录 一、Bear and Big Brother总结 一、Bear and Big Brother 本题链接:Bear and Big Brother 题目: A. Bear...


一、Bear and Big Brother

本题链接Bear and Big Brother

题目

A. Bear and Big Brother
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.

Right now, Limak and Bob weigh a and b respectively. It’s guaranteed that Limak’s weight is smaller than or equal to his brother’s weight.

Limak eats a lot and his weight is tripled after every year, while Bob’s weight is doubled after every year.

After how many full years will Limak become strictly larger (strictly heavier) than Bob?

Input
The only line of the input contains two integers a and b (1 ≤ a ≤ b ≤ 10) — the weight of Limak and the weight of Bob respectively.

Output
Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob.

Examples

input
4 7
output
2

input
4 9
output
3

input
1 1
output
1

Note
In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn’t larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Limak became larger than Bob after two years so you should print 2.

In the second sample, Limak’s and Bob’s weights in next years are: 12 and 18, then 36 and 36, and finally 108 and 72 (after three years). The answer is 3. Remember that Limak wants to be larger than Bob and he won’t be satisfied with equal weights.

In the third sample, Limak becomes larger than Bob after the first year. Their weights will be 3 and 2 then.

本博客给出本题截图

在这里插入图片描述
在这里插入图片描述

题意:两个数,一个数每次扩大3倍,另一个数每次扩大2倍,问第一个数什么时候比第二个数大
AC代码

#include <iostream>

using namespace std;

int main()
{
    int a, b, i;
    cin >> a >> b;
    
    for (i = 0; a <= b; i ++ )
        a *= 3, b *= 2;
        
    cout << i << endl;
    
    return 0;
}

  
 
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
  • 11
  • 12
  • 13
  • 14
  • 15
  • 16

总结

水题,不解释

文章来源: chen-ac.blog.csdn.net,作者:辰chen,版权归原作者所有,如需转载,请联系作者。

原文链接:chen-ac.blog.csdn.net/article/details/117413900

【版权声明】本文为华为云社区用户转载文章,如果您发现本社区中有涉嫌抄袭的内容,欢迎发送邮件进行举报,并提供相关证据,一经查实,本社区将立刻删除涉嫌侵权内容,举报邮箱: cloudbbs@huaweicloud.com
  • 点赞
  • 收藏
  • 关注作者

评论(0

0/1000
抱歉,系统识别当前为高风险访问,暂不支持该操作

全部回复

上滑加载中

设置昵称

在此一键设置昵称,即可参与社区互动!

*长度不超过10个汉字或20个英文字符,设置后3个月内不可修改。

*长度不超过10个汉字或20个英文字符,设置后3个月内不可修改。