python计算向量夹角代码
【摘要】
向左为负,向右为正,标准坐标系,返回-180-180度
import math AB = [0 ,0 ,5 ,-1]CD = [0 ,0 ,4.5 ,4.5]EF = [0 ,0 ,-2 ,6]PQ = [0 ,0 ,-6 ,-1] def angle(v1, v2): dx1 = v1[2] - v1[0] dy1 =...
向左为负,向右为正,标准坐标系,返回-180-180度
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import math
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AB = [0 ,0 ,5 ,-1]
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CD = [0 ,0 ,4.5 ,4.5]
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EF = [0 ,0 ,-2 ,6]
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PQ = [0 ,0 ,-6 ,-1]
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def angle(v1, v2):
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dx1 = v1[2] - v1[0]
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dy1 = v1[3] - v1[1]
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dx2 = v2[2] - v2[0]
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dy2 = v2[3] - v2[1]
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angle1 = math.atan2(dy1, dx1)
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angle1 = -int(angle1 * 180 /math.pi)
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if angle1<0:
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angle1=360+angle1
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# print(angle1)
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angle2 = math.atan2(dy2, dx2)
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angle2 =- int(angle2 * 180 /math.pi)
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if angle2 < 0:
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angle2 = 360 + angle2
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print(angle1,angle2)
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included_angle = angle1 - angle2
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if abs(included_angle) > 180:
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included_angle=included_angle/abs(included_angle)*(360-abs(included_angle))
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else:
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included_angle*=-1
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return included_angle
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ang1 = angle(AB, CD)
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print("AB和CD的夹角")
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print(ang1)
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ang1 = angle(CD,AB)
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print("CD和AB的夹角"
文章来源: blog.csdn.net,作者:AI视觉网奇,版权归原作者所有,如需转载,请联系作者。
原文链接:blog.csdn.net/jacke121/article/details/120190497
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