python获取重复元素

这个不错：

  

   

    

     

    
    

     

      from collections import Counter  # 引入Counter
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      list = [29, 36, 57, 12, 79, 43, 23, 56, 28, 11, 14, 15, 16, 37, 24, 35, 17, 24, 33, 15, 39, 46, 52, 13]
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      set = set(list)
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      for item in set:
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

       print("the %d has found %d" %(item,list.count(item)))
     
    
  
 

Counter：

  

   

    

     

    
    

     

      from collections import Counter  # 引入Counter
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      list = [29, 36, 57, 12, 79, 43, 23, 56, 28, 11, 14, 15, 16, 37, 24, 35, 17, 24, 33, 15, 39, 46, 52, 13]
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      aaa= Counter(list)
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      print(aaa)
     
    
  
 

可以根据上面的自己加工，想直接抄代码的，下面这个可以：

  

   

    

     

    
    

     

      from collections import Counter  # 引入Counter
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      a = [29, 36, 57, 12, 79, 43, 23, 56, 28, 11, 14, 15, 16, 37, 24, 35, 17, 24, 33, 15, 39, 46, 52, 13]
     
    
   

    

     

    
    

     

      b = dict(Counter(a))
     
    
   

    

     

    
    

     

      print([key for key, value in b.items() if value > 1])  # 只展示重复元素
     
    
   

    

     

    
    

     

      print({key: value for key, value in b.items() if value > 1})  # 展现重复元素和重复次数
     
    
  
 

测试结果展示：

[15, 24]
{15: 2, 24: 2}

文章来源: blog.csdn.net，作者：网奇，版权归原作者所有，如需转载，请联系作者。

原文链接：blog.csdn.net/jacke121/article/details/108238291