matlab循环矩阵
参考:http://www.ilovematlab.cn/thread-101148-1-1.html
这个ok:
clc;clear;
H=toeplitz(h,t)
这个也ok:
clc;clear;
h = [10 9 8 7 6 5 4 3 2 1];
size = length(h);
newh = zeros(size,size);
newh(1,1) = h(1);
newh(1,2:size) = h(size:-1:2);
for i = 2:size
newh(i,1) = newh(i-1,size);
newh(i,2:size) = newh(i-1,1:9);
end
这个也ok:
clear;
clc;
a = [1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 6 6 6 7 7 7 8 8 8];
h = [a;a;a];
%function producematrix(h,m)
[height width] = size(h);
m = 3;
c = cell(1,width/m);
for i = 1:m:width
c{(i+m-1)/m} = b(1:m,i:i+m-1);
end
newc = cell(length(c),length(c));
newc{1,1} = c{1};
for i = 2:length(c)
newc{1,i} = c{length(c)-i+2};
end
for i = 2:length(c)
newc{i,1} = newc{i-1,length(c)};
for j = 2:length(c)
newc{i,j} = newc{i-1,j-1};
end
end
%h和m是你的输入,m是h中构成方阵的大小;
对角化:
[V, D]= eig(newh)
D=inv(V)*newh*V
文章来源: blog.csdn.net,作者:网奇,版权归原作者所有,如需转载,请联系作者。
原文链接:blog.csdn.net/jacke121/article/details/62893854
- 点赞
- 收藏
- 关注作者
评论(0)