think python学习心得-（6）利用words.txt来进行填字游戏

练习9-1

  

   

    

     

    
    

     

      fin = open('C://words.txt')
     
    
   

    

     

    
    

     

      for line in fin:
     
    
   

    

     

    
    

     

       word = line.strip()
     
    
   

    

     

    
    

     
 if len(word) >20:
     
    
   

    

     

    
    

     
 print word
     
    
  
 

练习9-2

统计字母表中含有e的单词占有的百分比

  

   

    

     

    
    

     

      fin = open('C://words.txt')
     
    
   

    

     

    
    

     

      counter1 = 0
     
    
   

    

     

    
    

     

      counter2 = 0
     
    
   

    

     

    
    

     

      def has_no_e(wo):
     
    
   

    

     

    
    

     
 for i in range(len(wo)):
     
    
   

    

     

    
    

     
 if wo[i-1]=='e':
     
    
   

    

     

    
    

     
 return True
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      for line in fin:
     
    
   

    

     

    
    

     

       word = line.strip()
     
    
   

    

     

    
    

     

       flag = has_no_e(word)
     
    
   

    

     

    
    

     

       counter1=counter1+1
     
    
   

    

     

    
    

     
 if flag == True:
     
    
   

    

     

    
    

     

       counter2=counter2+1
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      counter1=float(counter1)
     
    
   

    

     

    
    

     

      counter2=float(counter2)
     
    
   

    

     

    
    

     

      print 100-counter2/counter1*100
     
    
  
 

利用下标循环实现输入文字中是否存在禁用字母的鉴别

  

   

    

     

    
    

     

      def avoids(word,forbiden):
     
    
   

    

     

    
    

     
 for i in range(len(forbiden)):
     
    
   

    

     

    
    

     
 for j in range(len(word)):
     
    
   

    

     

    
    

     
 if word[j-1]==forbiden[i-1]:
     
    
   

    

     

    
    

     
 return False
     
    
   

    

     

    
    

     
 return True
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      print 'Plesase input forbiden alphabet:'
     
    
   

    

     

    
    

     

      ban=raw_input('>')
     
    
   

    

     

    
    

     

      print 'Please input desired word:'
     
    
   

    

     

    
    

     

      test=raw_input('>>')
     
    
   

    

     

    
    

     

      print avoids(test,ban)
     
    
  
 

检测是否是由可用字符组成的

  

   

    

     

    
    

     

      def use_only(word,avaliable):
     
    
   

    

     

    
    

     
 for i in range(len(word)):
     
    
   

    

     

    
    

     

       flag=0
     
    
   

    

     

    
    

     
 for j in range(len(avaliable)):
     
    
   

    

     

    
    

     
 if word[i-1]==avaliable[j-1]:
     
    
   

    

     

    
    

     

       flag =1
     
    
   

    

     

    
    

     
 if flag==0:
     
    
   

    

     

    
    

     
 return False
     
    
   

    

     

    
    

     
 return True
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      print 'Plesase input avaliable alphabet:'
     
    
   

    

     

    
    

     

      ban=raw_input('>')
     
    
   

    

     

    
    

     

      print 'Please input desired word:'
     
    
   

    

     

    
    

     

      test=raw_input('>>')
     
    
   

    

     

    
    

     

      print use_only(test,ban)
     
    
  
 

练习9-5

检测alphebat是否被全部使用

  

   

    

     

    
    

     

      def uses_all(word,avaliable):
     
    
   

    

     

    
    

     

       counter=0
     
    
   

    

     

    
    

     
 for i in range(len(avaliable)):
     
    
   

    

     

    
    

     

       flag=0
     
    
   

    

     

    
    

     
 for j in range(len(word)):
     
    
   

    

     

    
    

     
 if word[j-1]==avaliable[i-1]:
     
    
   

    

     

    
    

     

       flag =1
     
    
   

    

     

    
    

     
 if flag==0:
     
    
   

    

     

    
    

     
 return False
     
    
   

    

     

    
    

     
 else:
     
    
   

    

     

    
    

     

       counter=counter+1
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     
 if counter == len(avaliable):
     
    
   

    

     

    
    

     
 return True
     
    
   

    

     

    
    

     
 else:
     
    
   

    

     

    
    

     
 return False
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      print 'Plesase input avaliable alphabet:'
     
    
   

    

     

    
    

     

      ban=raw_input('>')
     
    
   

    

     

    
    

     

      print 'Please input desired word:'
     
    
   

    

     

    
    

     

      test=raw_input('>>')
     
    
   

    

     

    
    

     

      print uses_all(test,ban)
     
    
  
 

  

   

    

     

    
    

     

      def is_abecedarian():
     
    
   

    

     

    
    

     

       fin = open ('C://words.txt')
     
    
   

    

     

    
    

     

       counter=0
     
    
   

    

     

    
    

     
 for line in fin:
     
    
   

    

     

    
    

     

       flag = 0
     
    
   

    

     

    
    

     
 for i in range(len(line)-1):
     
    
   

    

     

    
    

     
 if line[i]<=line[i+1]:
     
    
   

    

     

    
    

     

       flag=flag+1
     
    
   

    

     

    
    

     
 if flag==len(line)-2:
     
    
   

    

     

    
    

     

       counter=counter+1
     
    
   

    

     

    
    

     
 return counter
     
    
   

    

     

    
    

     

      print 'The number of abecedarian words in directionary is'
     
    
   

    

     

    
    

     

      print is_abecedarian()
     
    
  
 

QNMD车迷天下。。。。不做了

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原文链接：zclhit.blog.csdn.net/article/details/51038066