HDOJ1020 Encoding

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谙忆 发表于 2021/05/28 07:45:21 2021/05/28
【摘要】 Problem Description Given a string containing only ‘A’ - ‘Z’, we could encode it using the following method: Each sub-string containing k same characters should be encoded to “kX” whe...

Problem Description
Given a string containing only ‘A’ - ‘Z’, we could encode it using the following method:

  1. Each sub-string containing k same characters should be encoded to “kX” where “X” is the only character in this sub-string.

  2. If the length of the sub-string is 1, ‘1’ should be ignored.

Input
The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only ‘A’ - ‘Z’ and the length is less than 10000.

Output
For each test case, output the encoded string in a line.

Sample Input
2
ABC
ABBCCC

Sample Output
ABC
A2B3C

简单的字符串题目
需要注意的只有
如果输入:AABBBAAA
输出的是:2A3B3A
而不是:5A3B

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{ int s,i,j,n,p,m; char a[100000],temp; scanf("%d",&s); while(s--) { scanf("%s",a); n=strlen(a); temp=a[0]; m=1; for(i=1;i<=n;i++) { p=1; if(a[i]==temp) { m++; } if(a[i]!=temp) { p=0; temp=a[i]; } if(p==0) { if(m==1) printf("%c",a[i-1]); else printf("%d%c",m,a[i-1]); m=1; } } printf("\n"); } return 0;
}

  
 
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文章来源: chenhx.blog.csdn.net,作者:谙忆,版权归原作者所有,如需转载,请联系作者。

原文链接:chenhx.blog.csdn.net/article/details/48267025

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