【C语言】错题本(3)

题目:

​编辑

为了方便分析,我们将题目代码贴在下面:

int main()

{

unsigned char puc[4];

struct tagPIM

{

unsigned char ucPim1;

unsigned char ucData0 : 1;

unsigned char ucData1 : 2;

unsigned char ucData2 : 3;

}*pstPimData;

pstPimData = (struct tagPIM*)puc;

memset(puc,0,4);

pstPimData->ucPim1 = 2;

pstPimData->ucData0 = 3;

pstPimData->ucData1 = 4;

pstPimData->ucData2 = 5;

printf("%02x %02x %02x %02x\n",puc[0], puc[1], puc[2], puc[3]);

return 0;

}

正确答案:B

接下来画图分析一下题目:

​编辑

由图分析可知,最后puc[0]里存放的是00000010,puc[1]里存放的是00101001,puc[2]里存放的是00000000,puc[3]里存放的是00000000.用16进制打印出的结果即为:02 29 00 00.

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