圣诞将至:python3几行代码教你写出圣诞树。
【摘要】
今天咱们用python写个圣诞树玩玩 效果图: 源代码
# -----文件描述脚本------
# creatorName : 'ZiChen_Jiang'
# fileName : 'Christm...
今天咱们用python写个圣诞树玩玩
效果图:
源代码
# -----文件描述脚本------
# creatorName : 'ZiChen_Jiang'
# fileName : 'Christmas-python'
# createTime : '2021/12/20 09:24'
# Project introduction : 'Python3.9 构建的圣诞树解释文件'
# 执行命令 : python3 main.py
# ------文件描述脚本------
# 版本一
import turtle
screen = turtle.Screen()
screen.setup(800,600)
circle = turtle.Turtle()
circle.shape('circle')
circle.color('red')
circle.speed('fastest')
circle.up()
square = turtle.Turtle()
square.shape('square')
square.color('green')
square.speed('fastest')
square.up()
circle.goto(0,280)
circle.stamp()
k = 0
for i in range(1, 17):
y = 30*i
for j in range(i-k):
x = 30*j
square.goto(x,-y+280)
square.stamp()
square.goto(-x,-y+280)
square.stamp()
if i % 4 == 0:
x = 30*(j+1)
circle.color('red')
circle.goto(-x,-y+280)
circle.stamp()
circle.goto(x,-y+280)
circle.stamp()
k += 2
if i % 4 == 3:
x = 30*(j+1)
circle.color('yellow')
circle.goto(-x,-y+280)
circle.stamp()
circle.goto(x,-y+280)
circle.stamp()
square.color('brown')
for i in range(17,20):
y = 30*i
for j in range(3):
x = 30*j
square.goto(x,-y+280)
square.stamp()
square.goto(-x,-y+280)
square.stamp()
turtle.exitonclick()
# 版本二
# from turtle import *
# import random
# import time
#
# n = 80.0
#
# speed("fastest")
# screensize(bg='seashell')
# left(90)
# forward(3*n)
# color("orange", "yellow")
# begin_fill()
# left(126)
#
# for i in range(5):
# forward(n/5)
# right(144)
# forward(n/5)
# left(72)
# end_fill()
# right(126)
#
# color("dark green")
# backward(n*4.8)
# def tree(d, s):
# if d <= 0: return
# forward(s)
# tree(d-1, s*.8)
# right(120)
# tree(d-3, s*.5)
# right(120)
# tree(d-3, s*.5)
# right(120)
# backward(s)
# tree(15, n)
# backward(n/2)
#
# for i in range(200):
# a = 200 - 400 * random.random()
# b = 10 - 20 * random.random()
# up()
# forward(b)
# left(90)
# forward(a)
# down()
# if random.randint(0, 1) == 0:
# color('tomato')
# else:
# color('wheat')
# circle(2)
# up()
# backward(a)
# right(90)
# backward(b)
# time.sleep(60)
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文章来源: jiangwenxin.blog.csdn.net,作者:前端江太公,版权归原作者所有,如需转载,请联系作者。
原文链接:jiangwenxin.blog.csdn.net/article/details/122035761
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