UVa1586 - Molar mass

  

   

    

     

    
    

     

      //UVa1586 - Molar mass
     
    
   

    

     

    
    

     

      //给出一种由C, H, O, N 四种原子构成的分子式，求分子量
     
    
   

    

     

    
    

     

      //#define A1 //无法处理换行问题(scanf)
     
    
   

    

     

    
    

     

      //#define A2 //临界问题有BUG(sscanf)
     
    
   

    

     

    
    

     

      #define A3 //只考虑两位即可AC，直接暴力
     
    
   

    

     

    
    

     

      //#define A4 //考虑多位数有BUG
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      #ifdef A1
     
    
   

    

     

    
    

     

      #include<stdio.h>
     
    
   

    

     

    
    

     

      int main(){
     
    
   

    

     

    
    

     
	//freopen("data.in","r",stdin);
     
    
   

    

     

    
    

     
	int T;
     
    
   

    

     

    
    

     
	scanf("%d",&T);
     
    
   

    

     

    
    

     
	getchar();
     
    
   

    

     

    
    

     
	while(T--){
     
    
   

    

     

    
    

     
		char ch, ch2 = 'A'; int num; float M, ans = 0;
     
    
   

    

     

    
    

     
		//无法处理换行问题
     
    
   

    

     

    
    

     
		//while((ch2=getchar()) != EOF){
     
    
   

    

     

    
    

     
		while(scanf("%c",&ch2) == 1){
     
    
   

    

     

    
    

     
			if(ch2 == '\n'){if(ch >= 'C')ans += M; break;}
     
    
   

    

     

    
    

     
			else ch = ch2;
     
    
   

    

     

    
    

     
			if(ch == 'C') M = 12.01;
     
    
   

    

     

    
    

     
			if(ch == 'H') M = 1.008;
     
    
   

    

     

    
    

     
			if(ch == 'O') M = 16.00;
     
    
   

    

     

    
    

     
			if(ch == 'N') M = 14.01;
     
    
   

    

     

    
    

     
			if(scanf("%d",&num) != 1) ans += M;
     
    
   

    

     

    
    

     
			else ans += M*num;
     
    
   

    

     

    
    

     

      		}
     
    
   

    

     

    
    

     
		printf("%.3f\n", ans);
     
    
   

    

     

    
    

     

      	}
     
    
   

    

     

    
    

     
	return 0;
     
    
   

    

     

    
    

     

      }
     
    
   

    

     

    
    

     

      #endif
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      #ifdef A2
     
    
   

    

     

    
    

     

      #include<stdio.h>
     
    
   

    

     

    
    

     

      #include<string.h>
     
    
   

    

     

    
    

     

      #define maxn 20
     
    
   

    

     

    
    

     

      int bits(int x){
     
    
   

    

     

    
    

     
	if(x == 0)return 1;
     
    
   

    

     

    
    

     
	int count = 0;
     
    
   

    

     

    
    

     
	while(x>0){ count++; x/=10;}
     
    
   

    

     

    
    

     
	return count;
     
    
   

    

     

    
    

     

      }
     
    
   

    

     

    
    

     

      int main(){
     
    
   

    

     

    
    

     
	freopen("data.in","r",stdin);
     
    
   

    

     

    
    

     
	int T;
     
    
   

    

     

    
    

     
	scanf("%d",&T);
     
    
   

    

     

    
    

     
	getchar();
     
    
   

    

     

    
    

     
	while(T--){
     
    
   

    

     

    
    

     
		int num; float M, ans = 0;
     
    
   

    

     

    
    

     
		char str[maxn];
     
    
   

    

     

    
    

     
		fgets(str,maxn,stdin);
     
    
   

    

     

    
    

     
		//scanf("%s",str);
     
    
   

    

     

    
    

     
		for(int i = 0; i<strlen(str); i++){
     
    
   

    

     

    
    

     
			if(str[i] == 'C') M = 12.01;
     
    
   

    

     

    
    

     
			if(str[i] == 'H') M = 1.008;
     
    
   

    

     

    
    

     
			if(str[i] == 'O') M = 16.00;
     
    
   

    

     

    
    

     
			if(str[i] == 'N') M = 14.01;
     
    
   

    

     

    
    

     
			if(i == strlen(str)-1 && str[i]>='C'){ ans += M; break;}
     
    
   

    

     

    
    

     
			if(sscanf(&str[i+1],"%d",&num) != 1) ans += M;
     
    
   

    

     

    
    

     
			else {
     
    
   

    

     

    
    

     

      				i += bits(num);
     
    
   

    

     

    
    

     

      				ans += M*num;
     
    
   

    

     

    
    

     

      			}
     
    
   

    

     

    
    

     

      		}
     
    
   

    

     

    
    

     
		printf("%.3f\n", ans);
     
    
   

    

     

    
    

     

      	}
     
    
   

    

     

    
    

     
	return 0;
     
    
   

    

     

    
    

     

      }
     
    
   

    

     

    
    

     

      #endif
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      #ifdef A3
     
    
   

    

     

    
    

     

      #include<stdio.h>
     
    
   

    

     

    
    

     

      #include<string.h>
     
    
   

    

     

    
    

     

      #include<ctype.h> 
     
    
   

    

     

    
    

     

      #define maxn 100
     
    
   

    

     

    
    

     

      int main(){
     
    
   

    

     

    
    

     
	//freopen("data.in","r",stdin);
     
    
   

    

     

    
    

     
	int T;
     
    
   

    

     

    
    

     
	scanf("%d",&T);
     
    
   

    

     

    
    

     
	while(T--){
     
    
   

    

     

    
    

     
		char s[maxn]; scanf("%s",s);
     
    
   

    

     

    
    

     
		int n, a[4], len = strlen(s);
     
    
   

    

     

    
    

     
		memset(a,0,sizeof(a));
     
    
   

    

     

    
    

     
		for(int i = 0; i<len; i++){
     
    
   

    

     

    
    

     
			if(s[i] == 'C') n = 0;
     
    
   

    

     

    
    

     
			if(s[i] == 'H') n = 1;
     
    
   

    

     

    
    

     
			if(s[i] == 'O') n = 2;
     
    
   

    

     

    
    

     
			if(s[i] == 'N') n = 3;
     
    
   

    

     

    
    

     
			if(s[i]>='C')
     
    
   

    

     

    
    

     
			if(isdigit(s[i+1]) && isdigit(s[i+2])) a[n] += 10*(s[i+1]-'0')+(s[i+2]-'0');
     
    
   

    

     

    
    

     
			else a[n] += isdigit(s[i+1])? s[i+1]-'0': 1; 
     
    
   

    

     

    
    

     

      		}
     
    
   

    

     

    
    

     
		printf("%.3f\n", 12.01*a[0]+1.008*a[1]+16.00*a[2]+14.01*a[3]);
     
    
   

    

     

    
    

     

      	}
     
    
   

    

     

    
    

     
	return 0;
     
    
   

    

     

    
    

     

      }
     
    
   

    

     

    
    

     

      #endif
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     

      #ifdef A4
     
    
   

    

     

    
    

     

      #include<stdio.h>
     
    
   

    

     

    
    

     

      #include<string.h>
     
    
   

    

     

    
    

     

      int co(int cot){int add42=1; while(--cot)add42 *= 10; return add42;}
     
    
   

    

     

    
    

     

      int main(){
     
    
   

    

     

    
    

     
	freopen("data.in","r",stdin);
     
    
   

    

     

    
    

     
	int T;
     
    
   

    

     

    
    

     
	scanf("%d",&T);
     
    
   

    

     

    
    

     
	getchar();
     
    
   

    

     

    
    

     
	while(T--){
     
    
   

    

     

    
    

     
		char s[20];int a[4],n;
     
    
   

    

     

    
    

     
		memset(a,0,sizeof(a));
     
    
   

    

     

    
    

     
	//获取输入
     
    
   

    

     

    
    

     
		scanf("%s",s);
     
    
   

    

     

    
    

     
	//处理数据
     
    
   

    

     

    
    

     
		for(int i = 0; i < strlen(s); i++){
     
    
   

    

     

    
    

     
			if(s[i] > 57){//存储个数
     
    
   

    

     

    
    

     
				if(s[i] == 'C'){n=0;a[n]++;}
     
    
   

    

     

    
    

     
				if(s[i] == 'H'){n=1;a[n]++;}
     
    
   

    

     

    
    

     
				if(s[i] == 'O'){n=2;a[n]++;}
     
    
   

    

     

    
    

     
				if(s[i] == 'N'){n=3;a[n]++;}
     
    
   

    

     

    
    

     

      			}else{
     
    
   

    

     

    
    

     
				int count = 0;//记录数字位数
     
    
   

    

     

    
    

     
				for(int j = 0; ; j++){
     
    
   

    

     

    
    

     
					if(s[i+j] <= 57)count++;
     
    
   

    

     

    
    

     
					else break;
     
    
   

    

     

    
    

     
					printf("%d\n",j);
     
    
   

    

     

    
    

     

      				}
     
    
   

    

     

    
    

     
				while(count--){a[n] += (s[i+count]-'1')*co(count);printf("%d ",count);}
     
    
   

    

     

    
    

     

      			}
     
    
   

    

     

    
    

     

      		}
     
    
   

    

     

    
    

     
	//输出
     
    
   

    

     

    
    

     
		printf("%.3f\n",12.01*a[0]+1.008*a[1]+16.00*a[2]+14.01*a[3]);
     
    
   

    

     

    
    

     

      	}
     
    
   

    

     

    
    

     
	return 0;
     
    
   

    

     

    
    

     

      }
     
    
   

    

     

    
    

     

      #endif
     
    
   

    

     

    
    

     

      /*测试数据:
     
    
   

    

     

    
    

     

      4
     
    
   

    

     

    
    

     

      C
     
    
   

    

     

    
    

     

      C6H5OH
     
    
   

    

     

    
    

     

      NH2CH2COOH
     
    
   

    

     

    
    

     

      C12H22O11
     
    
   

    

     

    
    

     

      
     
    
   

    

     

    
    

     

      12.010
     
    
   

    

     

    
    

     

      94.108
     
    
   

    

     

    
    

     

      75.070
     
    
   

    

     

    
    

     

      342.296
     
    
   

    

     

    
    

     

      */
     
    
   

    

     

    
    

     
 
     
    
  
 

文章来源: gwj1314.blog.csdn.net，作者：小哈里，版权归原作者所有，如需转载，请联系作者。

原文链接：gwj1314.blog.csdn.net/article/details/54744418