062.浮点数转换为字符串
【摘要】
#include <stdio.h>#include <string.h> char c_je[51]; /*大写金额字符变量*/ char* zh( x ) /*数字金额转换为大写金额子程序*/double x; /*要...
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#include <stdio.h>
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#include <string.h>
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char c_je[51]; /*大写金额字符变量*/
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char* zh( x ) /*数字金额转换为大写金额子程序*/
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double x; /*要转换的金额数*/
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{
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int i, n, bz;
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char je[14]; /*数字金额的字符变量*/
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char temp[13];
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char f1[10][3] = {"零","壹","贰","叁","肆","伍",
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"陆","柒","捌","玖"}; /*数字对应的大写数组变量*/
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char f2[11][3] = {"亿","仟","佰","拾","万",
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"仟","佰","拾","元","角","分"}; /*每位数字对应单位数组变量*/
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sprintf( je, "%.01f", 100*x); /*转换成字符*/
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n = strlen( je );
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c_je[0] = '\0';
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bz = 1;
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for( i = 0; i < n; i++ )
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{
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strcpy( temp, &je[i] ); /*复制到临时数组*/
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if( atoi(temp)==0) /*判断第i位后是否全为0*/
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{
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bz = 2;
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break;
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}
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if( je[i] != '0' )
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{
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if( bz == 0 )
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strcat( c_je, f1[0] );
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strcat( c_je, f1[je[i] - '0'] ); /*数字串转化字符串*/
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bz = 1;
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strcat( c_je, f2[13-n+i]);
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}
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else
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{
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if( n-i == 7 && (je[i-1]!='0'||je[i-2]!='0' || je[i-3]!='0')) /*判断万位位置*/
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strcat( c_je, "万" );
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if( n-i == 3 ) /*判断个位数的元位置*/
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strcat( c_je, "元");
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bz = 0;
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}
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}
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if( bz == 2 )
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{
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if( n-i >= 7 && n-i < 10 )
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strcat( c_je, "万") ; /*万位数字为0,加‘万’*/
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if( n-i >= 3 )
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strcat( c_je, "元");
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strcat( c_je, "正" ); /*最后不是分位,加“正”*/
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}
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return c_je; /*返回大写金额*/
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}
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main()
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{
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double count;
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//clrscr();
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printf("*********************************************************\n");
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printf("* *\n");
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printf("* 数字金额转换为大写金额程序 Ver.1.0 *\n");
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printf("* *\n");
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printf("* By RZLIN *\n");
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printf("* *\n");
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printf("* 请输入要转换的金额: *\n");
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printf("* ");
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scanf("%lf", &count );
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printf("* 您输入的金额为:%10.2lf 。 *\n",count);
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printf("* *\n");
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printf("*转换为大写金额是:%s\n", zh( count ) );
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printf("* *\n");
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puts("* 请按任意键退出... *");
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printf("*********************************************************\n");
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getch();
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}
文章来源: blog.csdn.net,作者:程序员编程指南,版权归原作者所有,如需转载,请联系作者。
原文链接:blog.csdn.net/weixin_41055260/article/details/124495567
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