1、获取矩形两个点的数据(左上角和右下角)
SELECT *
FROM t_location
WHERE MBRContains
(
LineString(
Point (22.169,114.019 ),
Point ( 23.669, 114.939 )
), Location
)
2、获取周围10公里的数据,并按距离排序
SELECT
address,X(address_loc),Y(address_loc),
(2 * 6378.137 * ASIN(SQRT(POW(SIN(PI() * (:lat - X(p.shop_point)) / 360),2) + COS(PI() * :lat / 180) * COS(X(p.shop_point) * PI() / 180) * POW(SIN(PI() * (:lng - Y(p.shop_point)) / 360),2)))) as distance
FROM
address
WHERE
MBRContains (
LineString (
Point (
30.620076 + 10 / (
111.1 / COS(RADIANS(104.067221))
),
104.067221 + 10 / 111.1
),
Point (
30.620076 - 10 / (
111.1 / COS(RADIANS(104.067221))
),
104.067221 - 10 / 111.1
)
),
address_loc
)
ORDER BY distance;
3、详细查看
http://mysqlserverteam.com/mysql-5-7-and-gis-an-example/
原文:https://blog.csdn.net/u012274656/article/details/78529160
mysql 新特性之geometry
【摘要】
1、获取矩形两个点的数据(左上角和右下角)SELECT * FROM t_location WHERE MBRContains &...
文章来源: blog.csdn.net,作者:lxw1844912514,版权归原作者所有,如需转载,请联系作者。
原文链接:blog.csdn.net/lxw1844912514/article/details/100027818
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