Leetcode 题目解析之 H-Index
【摘要】 Leetcode 题目解析之 H-Index
Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher’s h-index.
According to the definition of h-index on Wikipedia: “A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each.”
For example, given citations = 3, 0, 6, 1, 5, which means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively. Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, his h-index is 3.
Note: If there are several possible values for h, the maximum one is taken as the h-index.
Hint:
- An easy approach is to sort the array first.
- What are the possible values of h-index?
- A faster approach is to use extra space.
题目描述不清,实际上,H-Index的核心计算方法是:
- 将某作者的所有文章的引用频次按照从大到小的位置排列
- 从前到后,找到最后一个满足条件的位置,其条件为:此位置是数组的第x个,其值为y,必须满足 y >= x;
public int hIndex(int[] citations) {
if (citations == null) {
return 0;
}
int h = 0, n = citations.length;
Arrays.sort(citations);
for (int i = n - 1; i >= 0; i--) {
if (citations[i] >= n - i) {
h = n - i;
} else {
break;
}
}
return h;
}
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