Leetcode 题目解析之 Minimum Size Subarray Sum
【摘要】 Leetcode 题目解析之 Minimum Size Subarray Sum
Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn’t one, return 0 instead.
For example, given the array 2,3,1,2,4,3 and s = 7,
the subarray 4,3 has the minimal length under the problem constraint.
More practice:
If you have figured out the O(n) solution, try coding another solution of which the time complexity is O(n log n).
定义两个指针,st和ed。如果sum>=s,sum从前面元素开始减;如果sum< s,ed++。
public int minSubArrayLen(int s, int[] nums) {
int sum = 0;
int st = 0;
int min = Integer.MAX_VALUE;
for (int i = 0; i < nums.length; i++) {
sum += nums[i];
if (sum >= s) {
while (sum - nums[st] >= s) {
sum -= nums[st++];
}
min = Math.min(min, i - st + 1);
}
}
if (min > nums.length) {
return 0;
}
return min;
}
【声明】本内容来自华为云开发者社区博主,不代表华为云及华为云开发者社区的观点和立场。转载时必须标注文章的来源(华为云社区)、文章链接、文章作者等基本信息,否则作者和本社区有权追究责任。如果您发现本社区中有涉嫌抄袭的内容,欢迎发送邮件进行举报,并提供相关证据,一经查实,本社区将立刻删除涉嫌侵权内容,举报邮箱:
cloudbbs@huaweicloud.com
- 点赞
- 收藏
- 关注作者
评论(0)