python基础之公共方法(十二)
运算符
运算符 | Python 表达式 | 结果 | 描述 | 支持的数据类型 |
---|---|---|---|---|
+ | [1, 2] + [3, 4] | [1, 2, 3, 4] | 合并 | 字符串、列表、元组 |
* | ‘Hi!’ * 4 | [‘Hi!’, ‘Hi!’, ‘Hi!’, ‘Hi!’] | 复制 | 字符串、列表、元组 |
in | 3 in (1, 2, 3) | True | 元素是否存在 | 字符串、列表、元组、字典 |
not in | 4 not in (1, 2, 3) | True | 元素是否不存在 | 字符串、列表、元组、字典 |
- +
>>> "hello " + "itcast"
'hello itcast'
>>> [1, 2] + [3, 4]
[1, 2, 3, 4]
>>> ('a', 'b') + ('c', 'd')
('a', 'b', 'c', 'd')
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- *
>>> 'ab'*4
'ababab'
>>> [1, 2]*4
[1, 2, 1, 2, 1, 2, 1, 2]
>>> ('a', 'b')*4
('a', 'b', 'a', 'b', 'a', 'b', 'a', 'b')
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- in
>>> 'itc' in 'hello itcast'
True
>>> 3 in [1, 2]
False
>>> 4 in (1, 2, 3, 4)
True
>>> "name" in {"name":"Delron", "age":24}
True
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注意,in在对字典操作时,判断的是字典的键
python内置函数
Python包含了以下内置函数
序号 | 方法 | 描述 |
---|---|---|
1 | cmp(item1, item2) | 比较两个值 |
2 | len(item) | 计算容器中元素个数 |
3 | max(item) | 返回容器中元素最大值 |
4 | min(item) | 返回容器中元素最小值 |
5 | del(item) | 删除变量 |
- cmp
>>> cmp("hello", "itcast")
-1
>>> cmp("itcast", "hello")
1
>>> cmp("itcast", "itcast")
0
>>> cmp([1, 2], [3, 4])
-1
>>> cmp([1, 2], [1, 1])
1
>>> cmp([1, 2], [1, 2, 3])
-1
>>> cmp({"a":1}, {"b":1})
-1
>>> cmp({"a":2}, {"a":1})
1
>>> cmp({"a":2}, {"a":2, "b":1})
-1
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注意:cmp在比较字典数据时,先比较键,再比较值。
- len
>>> len("hello itcast")
12
>>> len([1, 2, 3, 4])
4
>>> len((3,4))
2
>>> len({"a":1, "b":2})
2
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注意:len在操作字典数据时,返回的是键值对个数。
- max
>>> max("hello itcast")
't'
>>> max([1,4,522,3,4])
522
>>> max({"a":1, "b":2})
'b'
>>> max({"a":10, "b":2})
'b'
>>> max({"c":10, "b":2})
'c'
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- del
del有两种用法,一种是del加空格,另一种是del()
>>> a = 1
>>> a
1
>>> del a
>>> a
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Traceback (most recent call last):
File “”, line 1, in
NameError: name ‘a’ is not defined
>>> a = ['a', 'b']
>>> del a[0]
>>> a
['b']
>>> del(a)
>>> a
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Traceback (most recent call last):
File “”, line 1, in
NameError: name ‘a’ is not defined
多维列表/元祖访问的示例
>>> tuple1 = [(2,3),(4,5)]
>>> tuple1[0]
(2, 3)
>>> tuple1[0][0]
2
>>> tuple1[0][2]
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Traceback (most recent call last):
File “”, line 1, in
IndexError: tuple index out of range
>>> tuple1[0][1]
3
>>> tuple1[2][2]
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Traceback (most recent call last):
File “”, line 1, in
IndexError: list index out of range
>>> tuple2 = tuple1+[(3)]
>>> tuple2
[(2, 3), (4, 5), 3]
>>> tuple2[2]
3
>>> tuple2[2][0]
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Traceback (most recent call last):
File “”, line 1, in
TypeError: ‘int’ object is not subscriptable
文章来源: yujiang.blog.csdn.net,作者:鱼酱2333,版权归原作者所有,如需转载,请联系作者。
原文链接:yujiang.blog.csdn.net/article/details/89322169
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