一，游戏介绍

这是一个在线编写JS代码的游戏：http://play.elevatorsaga.com/

显示界面：

其中的doc是肯定要看的。

操作界面：

初始代码：

      {
         init: function(elevators, floors) {
             var elevator = elevators[0]; // Let's use the first elevator
             // Whenever the elevator is idle (has no more queued destinations) ...
              elevator.on("idle", function() {
                 // let's go to all the floors (or did we forget one?)
                  elevator.goToFloor(0);
                  elevator.goToFloor(1);
              });
          },
         update: function(dt, elevators, floors) {
             // We normally don't need to do anything here
          }
      }
  
 

二，闯关

第1关

初始代码有提示：let's go to all the floors (or did we forget one?)

本关代码：

      {
         init: function(elevators, floors) {
             var elevator = elevators[0]; // Let's use the first elevator
             // Whenever the elevator is idle (has no more queued destinations) ...
              elevator.on("idle", function() {
                 // let's go to all the floors (or did we forget one?)
                  elevator.goToFloor(0);
                  elevator.goToFloor(1);
                  elevator.goToFloor(2);
              });
          },
         update: function(dt, elevators, floors) {
             // We normally don't need to do anything here
          }
      }
  
 

第2关

      {
         init: function(elevators, floors) {
             var elevator = elevators[0]; // Let's use the first elevator
             var floor = floors[0];
             // Whenever the elevator is idle (has no more queued destinations) ...
              elevator.on("idle", function() {
                 //elevator.goToFloor(0);
              });
              elevator.on("floor_button_pressed", function(floorNum) {
                  elevator.destinationQueue.push(floorNum);
                  elevator.checkDestinationQueue();
              })
              floor.on("up_button_pressed", function() {
                  elevator.destinationQueue.push(floor.floorNum());
                  elevator.checkDestinationQueue();
              })
              floor.on("down_button_pressed", function() {
                  elevator.destinationQueue.push(floor.floorNum());
                  elevator.checkDestinationQueue();
              })
          },
         update: function(dt, elevators, floors) {
             // We normally don't need to do anything here
             var elevator = elevators[0]; // Let's use the first elevator
             for(var i=1;i<=4;i++){
                 if(elevator.destinationQueue.indexOf(i)>-1){
                      elevator.goToFloor(i);
                  }
              }
             for(var i=4;i>0;i--){
                 if(elevator.destinationQueue.indexOf(i)>-1){
                      elevator.goToFloor(i);
                  }
              }
          }
      }
  
 

第2关我居然都没能通过，主要是JS不熟，加上API没太看懂。。。

文章来源: blog.csdn.net，作者：csuzhucong，版权归原作者所有，如需转载，请联系作者。

原文链接：blog.csdn.net/nameofcsdn/article/details/118435947