Python全栈之路：集合set常用方法

集合：一个无序的，不重复的数据组合
- 去重，列表变集合，自动去重
- 关系测试，测试两组数据之间的交集，差集，并集等关系

去重

set0 = set("hello")  # 创建字符集合
print("set0:", set0)  # ->set0: {'e', 'l', 'h', 'o'}

list1 = [1, 2, 3, 1, 2]
set1 = set(list1)  # 创建数值集合
print(type(set1), set1)  # -><class 'set'> {1, 2, 3}

set2 = {1, 2, 4, 0}
set3 = {1, 2}
print("set1:", set1)  # ->set1: {1, 2, 3}
print("set2:", set2)  # ->set2: {0, 1, 2, 4}
print("set3:", set3)  # ->set3: {1, 2}
  

 

  
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关系测试

# 交集
print("set1 ∩ set2:", set1.intersection(set2))  # ->set1 ∩ set2: {1, 2}
print("set1 & et2:", set1 & set2)  # ->set1 & et2: {1, 2}

# 并集
print("set1 ∪ set2:", set1.union(set2))  # ->set1 ∪ set2: {0, 1, 2, 3, 4}
print("set1 | set2:", set1 | set2)  # ->set1 | set2: {0, 1, 2, 3, 4}

# 差集  in set1 but no in set2
print("set1-set2:", set1.difference(set2))   # ->set1-set2: {3}
print("set2-set1:", set2.difference(set1))  # ->set2-set1: {0, 4}
print("set1-set2:", set1 - set2)  # ->set1-set2: {3}
print("set2-set1:", set2 - set1)  # ->set2-set1: {0, 4}

# 对称差集  二者中不相交的部分
print("set1-set2 ∪ set2-set1:", set1.symmetric_difference(set2))
# ->set1-set2 ∪ set2-set1: {0, 3, 4}
print("set1 ^ set2:", set1 ^ set2)  # ->set1 ^ set2: {0, 3, 4}

# 子集
print("set3∈set1?:",set3.issubset(set1))  # ->set3∈set1?: True
print("set3 <= set1:",set3.issubset(set1))  # ->set3 <= set1: True
# 父集
print("set3∈set1?:",set1.issuperset(set3))   # ->set3∈set1?: True
print("set1 >= set3:",set1.issuperset(set3))  # ->set1 >= set3: True

# 相等
print("set1 == set2", set1 == set2)  #->set1 == set2 False
print("set1 != set2", set1 != set2)  #->set1 != set2 True

# 不相交
set4 = {5, 6, 7}
print(set4)  # ->{5, 6, 7}
print("set1∩set2==null?", set1.isdisjoint(set2))
# ->set1∩set2==null? False
print("set1∩set4==null?", set1.isdisjoint(set4))
# ->set1∩set4==null? True
  

 

  
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基本操作

# 添加
print(set1)  # ->{1, 2, 3}
set1.add(5)  # 添加一项
print(set1)  # ->{1, 2, 3, 5}
set1.update([6, 7, 8, 8])  #添加多项
print(set1)  # ->{1, 2, 3, 5, 6, 7, 8}

# 删除
set1.remove(5)  # 指定删除,不存在会报错
print(set1)  # ->{1, 2, 3, 6, 7, 8}
set1.pop()  # 随意删除
print(set1)  # ->{2, 3, 6, 7, 8}
set1.discard(888)  # 指定删除，不存在不会报错

# 长度
print(len(set1))  # ->5

# 成员检查,字符串，列表，集合，字典
print(6 in set1)  # ->True
print(9 not in set1)  # ->True
  

 

  
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文章来源: pengshiyu.blog.csdn.net，作者：彭世瑜，版权归原作者所有，如需转载，请联系作者。

原文链接：pengshiyu.blog.csdn.net/article/details/78885157