Python编程：从网络地址中解析出系统文件路径

# -*- coding: utf-8 -*-

# 从网络地址中解析出系统文件路径
from urlparse import urlparse  #py2版本， py3不一样
from os.path import basename, dirname, join

url = "https://matplotlib.org/_downloads/font_file.py"

parse_result = urlparse(url)
print parse_result

path = parse_result.path
print path

print join(basename(dirname(path)), basename(path))

"""
ParseResult(scheme='https', netloc='matplotlib.org', path='/_downloads/font_file.py', params='', query='', fragment='')
/_downloads/font_file.py
_downloads/font_file.py
"""
  

 

  
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文章来源: pengshiyu.blog.csdn.net，作者：彭世瑜，版权归原作者所有，如需转载，请联系作者。

原文链接：pengshiyu.blog.csdn.net/article/details/80097624