Python爬虫：Scrapy链接解析器LinkExtractor返回Link对象

LinkExtractor

from scrapy.linkextractors import LinkExtractor


  

 

  
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Link

from scrapy.link import Link

  

 

  
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Link四个属性

url text fragment nofollow


  

 

  
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如果需要解析出文本，需要在 LinkExtractor 的参数中添加参数：attrs

link_extractor = LinkExtractor(attrs=('href','text'))

links = link_extractor.extract_links(response)

  

 

  
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使用示例

import scrapy

from scrapy.linkextractors import LinkExtractor


class DemoSpider(scrapy.Spider): name = 'spider' start_urls = [ "https://book.douban.com/" ] def parse(self, response): # 参数是正则表达式 link_extractor = LinkExtractor(allow="https://www.tianyancha.com/brand/b.*") links = link_extractor.extract_links(response) for link in links: print(link.text, link.url)


if __name__ == '__main__': cmdline.execute("scrapy crawl spider".split())


  

 

  
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文章来源: pengshiyu.blog.csdn.net，作者：彭世瑜，版权归原作者所有，如需转载，请联系作者。

原文链接：pengshiyu.blog.csdn.net/article/details/80538752