Java 复数_2

复数的高阶运算：复正弦，复余弦，复对数，复指数

  

   

    

     

    
    

     
 package cn.jzsz;
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     
 public class fushu2
     
    
   

    

     

    
    

     

       {
     
    
   

    

     

    
    

     
 //复对数运算
     
    
   

    

     

    
    

     
 static void cLog(double a, double b, double[] e, double[] f)
     
    
   

    

     

    
    

     

       {
     
    
   

    

     

    
    

     
 double temp;
     
    
   

    

     

    
    

     

       temp = Math.log(Math.sqrt(a * a + b * b));
     
    
   

    

     

    
    

     

       e[0] = temp; f[0] = Math.atan2(b, a);
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     
 //复指数运算e的(a+bi)次幂
     
    
   

    

     

    
    

     
 public static void mi(double a,double b,double[] e,double[] f){
     
    
   

    

     

    
    

     
 double temp;
     
    
   

    

     

    
    

     

       temp = (double)Math.exp(a);
     
    
   

    

     

    
    

     

       e[0]=temp*(double)Math.cos(b);
     
    
   

    

     

    
    

     

       f[0]=temp*(double)Math.sin(a);}
     
    
   

    

     

    
    

     
 //复正弦运算
     
    
   

    

     

    
    

     
 public static void sin(double a,double b,double[] e,double[] f){
     
    
   

    

     

    
    

     
 double q,p;
     
    
   

    

     

    
    

     

       p =Math.exp(b);
     
    
   

    

     

    
    

     

       q =1/p;e[0]=Math.sin(a)*(q+p)/2.0;
     
    
   

    

     

    
    

     

       f[0]=Math.cos(a)*(p-q)/2.0;
     
    
   

    

     

    
    

     

       } 
     
    
   

    

     

    
    

     
 //复余弦 //复余弦运算
     
    
   

    

     

    
    

     
 public static void cos(double a, double b, double[] e, double[] f) {
     
    
   

    

     

    
    

     
 double q, p;
     
    
   

    

     

    
    

     

       p = Math.exp(b);
     
    
   

    

     

    
    

     

       q = 1 / p;
     
    
   

    

     

    
    

     

       e[0] = Math.cos(a) * (q + p) / 2.0;
     
    
   

    

     

    
    

     

       f[0] = -1.0 * Math.sin(a) * (p - q) / 2.0;
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     
 public static void ln(double a, double b, double[] e, double[] f) {
     
    
   

    

     

    
    

     

       e[0] = Math.log(Math.sqrt(a * a + b * b));
     
    
   

    

     

    
    

     

       f[0] = Math.atan2(b, a);
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     
 public static void main(String[] args) {
     
    
   

    

     

    
    

     
 double a, b;
     
    
   

    

     

    
    

     
 double[] e = { 0 }, f = { 0 };
     
    
   

    

     

    
    

     

       a = 2.0; b = 3.0; cLog(a, b, e, f);
     
    
   

    

     

    
    

     

       System.out.println(e[0] + "+" + f[0]);
     
    
   

    

     

    
    

     

       mi(a, b, e, f);
     
    
   

    

     

    
    

     

       System.out.println(e[0] + "+" + f[0]);
     
    
   

    

     

    
    

     

       sin(a, b, e, f);
     
    
   

    

     

    
    

     

       System.out.println(e[0] + "+" + f[0]);
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     

      }
     
    
  
 

文章来源: czhenya.blog.csdn.net，作者：陈言必行，版权归原作者所有，如需转载，请联系作者。

原文链接：czhenya.blog.csdn.net/article/details/77610783