Java 复数_1
【摘要】 复数的四则基础运算:
package cn.jzsz; public class fushu {static void cPlus(double a,double b,double c,double d,double[] e,double[] f){ e[0]=a+c; f[0]=b+d;}static void cMinus(double a,double b,dou...
复数的四则基础运算:
-
package cn.jzsz;
-
-
public class fushu {
-
static void cPlus(double a,double b,double c,double d,double[] e,double[] f){
-
e[0]=a+c;
-
f[0]=b+d;
-
}
-
static void cMinus(double a,double b,double c,double d,double[] e,double[] f){
-
e[0]=a-c;
-
f[0]=b-d;
-
}
-
static void cMu1(double a,double b,double c,double d,double[] e,double[] f){
-
e[0]=a*c-b*d;
-
f[0]=a*d+c*b;
-
}
-
static void cDiv(double a,double b,double c,double d,double[] e,double[] f){
-
double sq;
-
sq=c*c+d*d;
-
e[0]=(a*c+b*d)/sq;
-
f[0]=(b*c-a*d)/sq;
-
}
-
static void cPown(double a,double b,int n,double[] e,double[] f){
-
double result;
-
int i;
-
e[0]=a;f[0]=b;
-
if(n==1){
-
return;
-
}else{
-
cMu1(e[0],f[0],a,b,e,f);
-
}}
-
static void cExp(double a,double b,double[] e,double[] f){
-
double temp;
-
temp=Math.exp(a);
-
e[0]=temp*Math.cos(b);
-
f[0]=temp*Math.sin(b);
-
}
-
public static void main(String[] args) {
-
double a,b,c,d;
-
double[] e={0},f={0};
-
a=4;b=6;
-
c=2;d=-1;
-
cPlus(a,b,c,d,e,f);
-
System.out.println(e[0]+"+"+f[0]+"i");
-
cMinus(a,b,c,d,e,f);
-
System.out.println(e[0]+"+"+f[0]+"i");
-
cMu1(a,b,c,d,e,f);
-
System.out.println(e[0]+"+"+f[0]+"i");
-
cDiv(a,b,c,d,e,f);
-
System.out.println(e[0]+"+"+f[0]+"i");
-
cPown(a,b,5,e,f);
-
System.out.println(e[0]+"+"+f[0]+"i");
-
cExp(a,b,e,f);
-
System.out.println(e[0]+"+"+f[0]+"i");
-
}
-
}
文章来源: czhenya.blog.csdn.net,作者:陈言必行,版权归原作者所有,如需转载,请联系作者。
原文链接:czhenya.blog.csdn.net/article/details/77610741
【版权声明】本文为华为云社区用户转载文章,如果您发现本社区中有涉嫌抄袭的内容,欢迎发送邮件进行举报,并提供相关证据,一经查实,本社区将立刻删除涉嫌侵权内容,举报邮箱:
cloudbbs@huaweicloud.com
- 点赞
- 收藏
- 关注作者
评论(0)