C++--重载(非成员函数):复数加减法
【摘要】 测试代码
#include<iostream>
#include<string>
using std::ostream;
using std::cin;
using std::cout;
using std::endl;
class complex{
public:
complex(double a=0.0,double b=0.0):a(...
测试代码
#include<iostream>
#include<string>
using std::ostream;
using std::cin;
using std::cout;
using std::endl;
class complex{
public:
complex(double a=0.0,double b=0.0):a(a),b(b){ cout<<"构造函数被调用!"<<endl;
}
~complex(){ cout<<"析构函数被调用!"<<endl;
}
friend complex operator + (const complex &c1,const complex &c2)
{
return complex((c1.a+c2.a),(c1.b+c2.b));
}
friend complex operator - (const complex &c1,const complex &c2)
{
return complex((c1.a-c2.a),(c1.b-c2.b));
} friend ostream & operator << (ostream &out ,const complex &c)
{ out<<"("<<c.a<<","<<c.b<<")"<<endl; return out;
}
private:
double a;
double b;
};
int main()
{
complex a1(2,2);
complex a2(4,4);
complex a3;
a3=a1+a2;
cout<<a3;
return 0;
}
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
程序运行界面
文章来源: haihong.blog.csdn.net,作者:海轰Pro,版权归原作者所有,如需转载,请联系作者。
原文链接:haihong.blog.csdn.net/article/details/105370834
【版权声明】本文为华为云社区用户转载文章,如果您发现本社区中有涉嫌抄袭的内容,欢迎发送邮件进行举报,并提供相关证据,一经查实,本社区将立刻删除涉嫌侵权内容,举报邮箱:
cloudbbs@huaweicloud.com
- 点赞
- 收藏
- 关注作者
评论(0)