LeetCode之Detect Capital
【摘要】 1、题目
Given a word, you need to judge whether the usage of capitals in it is right or not.
We define the usage of capitals in a word to be right when one of the following cases hol...
1、题目
Given a word, you need to judge whether the usage of capitals in it is right or not.
We define the usage of capitals in a word to be right when one of the following cases holds:
- All letters in this word are capitals, like "USA".
- All letters in this word are not capitals, like "leetcode".
- Only the first letter in this word is capital if it has more than one letter, like "Google".
Otherwise, we define that this word doesn't use capitals in a right way.
Example 1:
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Input: "USA"
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Output: True
Example 2:
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Input: "FlaG"
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Output: False
Note:The input will be a non-empty word consisting of uppercase and lowercase latin letters.
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2、代码实现
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public class Solution {
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public boolean detectCapitalUse(String word) {
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if (word == null || word.length() == 0)
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return false;
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if (word.length() == 1)
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return true;
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int length = word.length();
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if (word.charAt(0) >= 65 && word.charAt(0) <= 90) {
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//AA**
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if (word.charAt(1) >= 65 && word.charAt(1) <= 90) {
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if (length > 2) {
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//AA*a*
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for (int i = 2 ; i < length; ++i) {
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if (word.charAt(i) >= 97 && word.charAt(i) <= 122)
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return false;
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}
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//AAA
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return true;
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} else {
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//AA
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return true;
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}
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}
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//Aa**
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if (word.charAt(1) >= 97 && word.charAt(1) <= 122) {
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if (length > 2) {
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for (int i = 2 ; i < length; ++i) {
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//Aa*A*
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if (word.charAt(i) >= 65 && word.charAt(i) <= 90)
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return false;
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}
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//Aaa
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return true;
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} else {
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//Aa
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return true;
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}
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}
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} else {
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//aAa
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for (int i = 1; i < length; i++) {
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if (word.charAt(i) >= 65 && word.charAt(i) <= 90)
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return false;
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}
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//aaa
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return true;
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}
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return false;
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}
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}
文章来源: chenyu.blog.csdn.net，作者：chen.yu，版权归原作者所有，如需转载，请联系作者。
原文链接：chenyu.blog.csdn.net/article/details/69654563
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