LeetCode之Rotate Array
【摘要】 1、题目
Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated t...
1、题目
Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7]
is rotated to [5,6,7,1,2,3,4]
.
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
Related problem: Reverse Words in a String II
Credits:
Special thanks to @Freezen for adding this problem and creating all test cases.
2、结题思路
1、先得到有效的k,
2、反转所有数组
3、反转下标从0到k的数组
4、 反转下标从k到length - 1的数组
3、代码实现
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class Solution {
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public void rotate(int[] nums, int k) {
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if (nums == null || nums.length == 0 || k <= 0)
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return;
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int length = nums.length;
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int lastK = 0;
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if (k < length)
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lastK = k;
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else
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lastK = k % length;
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if (lastK == 0)
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return;
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change(nums, length);
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change(nums, lastK);
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int i = lastK, j = length - 1;
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while (i < j) {
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int temp = nums[i];
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nums[i] = nums[j];
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nums[j] = temp;
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i++;
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j--;
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}
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}
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public void change(int[] nums, int length) {
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for (int i = 0; i < length / 2; ++i) {
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int temp = nums[i];
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nums[i] = nums[length - i - 1];
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nums[length - i - 1] = temp;
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}
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}
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}
文章来源: chenyu.blog.csdn.net,作者:chen.yu,版权归原作者所有,如需转载,请联系作者。
原文链接:chenyu.blog.csdn.net/article/details/78014922
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