leetcode 刷题 77 78
【摘要】
class Solution: def combine(self, n: int, k: int) -> List[List[int]]: def search(cur, remain): if remain == 0: return [[]] return [[c] + next for c in range(cur, n+2-remain) for nex...
class Solution: def combine(self, n: int, k: int) -> List[List[int]]: def search(cur, remain): if remain == 0: return [[]] return [[c] + next for c in range(cur, n+2-remain) for next in search(c+1, remain-1)] return search(1, k)
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class Solution(object): def combine(self, n, k): """ :type n: int :type k: int :rtype: List[List[int]] """ result = [] def dfs(stack, num, k): if k == 0: result.append(stack) return for i in reversed(range(1, num + 1)): if k > i: break dfs(stack + [i], i - 1, k - 1) dfs([], n, k) return result
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class Solution: def subsets(self, nums: List[int]) -> List[List[int]]: d = [] d.append([]) for x in nums: l = len(d) for i in range(l): t = [x] d.append(t+d[i]) return d #一行
#return [[x for b, x in zip(("{:0" + str(len(nums)) + "b}").format(n), nums) if b == '1'] for n in range(2 ** len(nums))]
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文章来源: maoli.blog.csdn.net,作者:刘润森!,版权归原作者所有,如需转载,请联系作者。
原文链接:maoli.blog.csdn.net/article/details/90543887
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