sql高级练习

--alias table name 表重命名

select id, name, s.id, s.name from student s;

--column 列运算

select (age + id) col from student;

select s.name + '-' + c.name from classes c, student s where s.cid = c.id;

--where 条件

select * from student where id = 2;

select * from student where id > 7;

select * from student where id < 3;

select * from student where id <> 3;

select * from student where id >= 3;

select * from student where id <= 5;

select * from student where id !> 3;

select * from student where id !< 5;

--and 并且

select * from student where id > 2 and sex = 1;

--or 或者

select * from student where id = 2 or sex = 1;

--between ... and ... 相当于并且

select * from student where id between 2 and 5;

select * from student where id not between 2 and 5;

--like 模糊查询

select * from student where name like  '%a%';

select * from student where name like  '%[a][o]%';

select * from student where name not like  '%a%';

select * from student where name like 'ja%';

select * from student where name not like '%[j,n]%';

select * from student where name like '%[j,n,a]%';

select * from student where name like '%[^ja,as,on]%';

select * from student where name like '%[ja_on]%';

--in 子查询

select * from student where id in (1, 2);

--not in 不在其中

select * from student where id not in (1, 2);

--is null 是空

select * from student where age is null;

--is not null 不为空

select * from student where age is not null;

--order by 排序

select * from student order by name;

select * from student order by name desc;

select * from student order by name asc;

--group by 分组

按照年龄进行分组统计

select count(age), age from student group by age;

按照性别进行分组统计

select count(*), sex from student group by sex;

按照年龄和性别组合分组统计，并排序

select count(*), sex from student group by sex, age order by age;

按照性别分组，并且是id大于2的记录最后按照性别排序

select count(*), sex from student where id > 2 group by sex order by sex;

查询id大于2的数据，并完成运算后的结果进行分组和排序

select count(*), (sex * id) new from student where id > 2 group by sex * id order by sex * id;