POJ 2027 No Brainer

Problem Description
Zombies love to eat brains. Yum.

Input
The first line contains a single integer n indicating the number of data sets.

The following n lines each represent a data set. Each data set will be formatted according to the following description:

A single data set consists of a line “X Y”, where X is the number of brains the zombie eats and Y is the number of brains the zombie requires to stay alive.

Output
For each data set, there will be exactly one line of output. This line will be “MMM BRAINS” if the number of brains the zombie eats is greater than or equal to the number of brains the zombie requires to stay alive. Otherwise, the line will be “NO BRAINS”.

Sample Input
3
4 5
3 3
4 3

Sample Output
NO BRAINS
MMM BRAINS
MMM BRAINS

简单的比大小。。。

#include <stdio.h>
#include <stdlib.h>

int main(){ int c; scanf("%d",&c); while(c--){ int x,y; scanf("%d %d",&x,&y); if(x<y) printf("NO BRAINS\n"); else printf("MMM BRAINS\n"); } return 0;
}
  

 

  
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文章来源: chenhx.blog.csdn.net，作者：谙忆，版权归原作者所有，如需转载，请联系作者。

原文链接：chenhx.blog.csdn.net/article/details/49428349