HDOJ 1076 An Easy Task（闰年计算）

Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output
For each test case, you should output the Nth leap year from year Y.

Sample Input
3
2005 25
1855 12
2004 10000

Sample Output
2108
1904
43236

Hint：
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

题意就是：输入一个年份year和一个n，求这个year之后的第n个闰年，
如果year是闰年，则算第一个闰年。

直接暴力做，并没有超时。

import java.util.Scanner;

public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while(t-->0){ int year = sc.nextInt(); int n = sc.nextInt(); int nyear = 0; if((year%4==0&&year%100!=0)|(year%400==0)){ nyear=1; }//如果year是闰年，nyear就加一 while(nyear<n){//当nyear小于n时，就循环 year++; if((year%4==0&&year%100!=0)|(year%400==0)){ nyear++; }//year是闰年，nyear就加加 } System.out.println(year); } }

}

  

 

  
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文章来源: chenhx.blog.csdn.net，作者：谙忆，版权归原作者所有，如需转载，请联系作者。

原文链接：chenhx.blog.csdn.net/article/details/51037949