HDOJ 2055 An easy problem

Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output
for each case, you should the result of y+f(x) on a line.

Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output
19
18
10
-17
-14
-4

题意：we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;Give you a letter x and a number y , you should output the result of y+f(x)..

import java.util.Scanner;

public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String lowerCase = "0abcdefghijklmnopqrstuvwxyz"; String capital = "1ABCDEFGHIJKLMNOPQRSTUVWXYZ"; int n =sc.nextInt(); //sc.next(); while(n-->0){ String strs = sc.next(); //System.out.println(strs); int y = sc.nextInt(); char x = strs.charAt(0); //strs = strs.substring(2); //int y = Integer.parseInt(strs,10); //System.out.println(x); //System.out.println(y); int g=0,h=0; for(int i=1;i<lowerCase.length();i++){ if(x==lowerCase.charAt(i)){ g=-i; break; } } for(int i=1;i<capital.length();i++){ if(x==capital.charAt(i)){ h=i; break; } } System.out.println(y+g+h); } }

}

  

 

  
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文章来源: chenhx.blog.csdn.net，作者：谙忆，版权归原作者所有，如需转载，请联系作者。

原文链接：chenhx.blog.csdn.net/article/details/50595655