HDOJ 2057 A + B Again

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谙忆 发表于 2021/05/28 05:59:06 2021/05/28
【摘要】 Problem Description There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it ...

Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output
For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output
0
2C
11
-2C
-90

import java.util.Scanner;

public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while(sc.hasNext()){ long str1 = sc.nextLong(16); long str2 = sc.nextLong(16); long a = str1+str2; if(a<0){ //System.out.println(a); a=-a; //System.out.println(a); System.out.println("-"+Long.toHexString(a).toUpperCase()); }else{ System.out.println(Long.toHexString(a).toUpperCase()); } } }

}

  
 
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文章来源: chenhx.blog.csdn.net,作者:谙忆,版权归原作者所有,如需转载,请联系作者。

原文链接:chenhx.blog.csdn.net/article/details/50603124

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