HDOJ(HDU) 1985 Conversions(汇率转换)

Problem Description
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

Sample Input
5
1 kg
2 l
7 lb
3.5 g
0 l

Sample Output
1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g

题目很简单，就是给出了汇率，让你转换！！！
水题！

import java.util.Scanner;

public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); String[] str1 = {"kg","l","lb","g"}; String[] str2 = {"lb","g","kg","l"}; double[]  d = {2.2046,0.2642,0.4536,3.7854}; int time = 1; int t = sc.nextInt(); while(t-->0){ int k=0; double n = sc.nextDouble(); String s = sc.next(); for(int i=0;i<str1.length;i++){ if(s.equals(str1[i])){ k=i; n = n*d[i]; break; } } System.out.printf("%d %.4f %s",time,n,str2[k] ); System.out.println(); time++; } }

}

  

 

  
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文章来源: chenhx.blog.csdn.net，作者：谙忆，版权归原作者所有，如需转载，请联系作者。

原文链接：chenhx.blog.csdn.net/article/details/51223820