HDOJ(HDU) 2123 An easy problem(简单题...)

Problem Description
In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the ith row and jth column should be the product(乘积) of i and j.

Input
The first line of input is an integer C which indicate the number of test cases.

Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.

Output
For each test case, print out the multiply table.

Sample Input
2
1
4

Sample Output
1
1 2 3 4
2 4 6 8
3 6 9 12
4 8 12 16

就是输入t个数，对于每个数n，输出n*n个数。
i为1-n，j为1-n，输出i*j。
每一行最后一个输出后面没有空格啊！！！

import java.util.Scanner;

public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t =sc.nextInt(); while(t-->0){ int n =sc.nextInt(); for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ if(j==1){ System.out.print(i*j); }else{ System.out.print(" "+i*j); } } System.out.println(); } } }
}

  

 

  
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文章来源: chenhx.blog.csdn.net，作者：谙忆，版权归原作者所有，如需转载，请联系作者。

原文链接：chenhx.blog.csdn.net/article/details/51306220