leetcode85. 最大矩形

给定一个仅包含 0 和 1 的二维二进制矩阵，找出只包含 1 的最大矩形，并返回其面积。

示例:

输入:
[
  ["1","0","1","0","0"],
  ["1","0","1","1","1"],
  ["1","1","1","1","1"],
  ["1","0","0","1","0"]
]
输出: 6

和leetcode84没什么区别，就是一行一行更新出“高度”，一行一行的跑一遍单调栈即可。

  

   

    

     

    
    

     

      class Solution {
     
    
   

    

     

    
    

     
 public int leetcode84(int[] heights) {
     
    
   

    

     

    
    

     

       Stack < Integer > stack = new Stack < > ();
     
    
   

    

     

    
    

     

       stack.push(-1);
     
    
   

    

     

    
    

     
 int maxarea = 0;
     
    
   

    

     

    
    

     
 for (int i = 0; i < heights.length; ++i) {
     
    
   

    

     

    
    

     
 while (stack.peek() != -1 && heights[stack.peek()] >= heights[i])
     
    
   

    

     

    
    

     

       maxarea = Math.max(maxarea, heights[stack.pop()] * (i - stack.peek() - 1));
     
    
   

    

     

    
    

     

       stack.push(i);
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     
 while (stack.peek() != -1)
     
    
   

    

     

    
    

     

       maxarea = Math.max(maxarea, heights[stack.pop()] * (heights.length - stack.peek() -1));
     
    
   

    

     

    
    

     
 return maxarea;
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     
 public int maximalRectangle(char[][] matrix) {
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     
 if (matrix.length == 0) return 0;
     
    
   

    

     

    
    

     
 int maxarea = 0;
     
    
   

    

     

    
    

     
 int[] dp = new int[matrix[0].length];
     
    
   

    

     

    
    

     
 
     
    
   

    

     

    
    

     
 for(int i = 0; i < matrix.length; i++) {
     
    
   

    

     

    
    

     
 for(int j = 0; j < matrix[0].length; j++) {
     
    
   

    

     

    
    

     

       dp[j] = matrix[i][j] == '1' ? dp[j] + 1 : 0;
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     

       maxarea = Math.max(maxarea, leetcode84(dp));
     
    
   

    

     

    
    

     

       } return maxarea;
     
    
   

    

     

    
    

     

       }
     
    
   

    

     

    
    

     

      }
     
    
  
 

文章来源: fantianzuo.blog.csdn.net，作者：兔老大RabbitMQ，版权归原作者所有，如需转载，请联系作者。

原文链接：fantianzuo.blog.csdn.net/article/details/104027791