leetcode1050. 合作过至少三次的演员和导演(SQL)
ActorDirector 表:
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| actor_id | int |
| director_id | int |
| timestamp | int |
+-------------+---------+
timestamp 是这张表的主键.
写一条SQL查询语句获取合作过至少三次的演员和导演的 id 对 (actor_id, director_id)
示例:
ActorDirector 表:
+-------------+-------------+-------------+
| actor_id | director_id | timestamp |
+-------------+-------------+-------------+
| 1 | 1 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 2 |
| 1 | 2 | 3 |
| 1 | 2 | 4 |
| 2 | 1 | 5 |
| 2 | 1 | 6 |
+-------------+-------------+-------------+
Result 表:
+-------------+-------------+
| actor_id | director_id |
+-------------+-------------+
| 1 | 1 |
+-------------+-------------+
唯一的 id 对是 (1, 1),他们恰好合作了 3 次。
思路:分组,注意group by可以对多个字段使用。
-
select actor_id,director_id
-
from ActorDirector
-
group by actor_id ,director_id
-
having count(*)>=3;
文章来源: fantianzuo.blog.csdn.net,作者:兔老大RabbitMQ,版权归原作者所有,如需转载,请联系作者。
原文链接:fantianzuo.blog.csdn.net/article/details/104397405
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