python学习实例(2)
【摘要】 #===================================#2.2 不同进制间的转换#=================================== #+++++++++++++++++++++++++++++++++++#2.2.1. 二进制数转换为十进制数#+++++++++++++++++++++++++++++++++++ #<程序:2-...
#===================================
#2.2 不同进制间的转换
#===================================
#+++++++++++++++++++++++++++++++++++
#2.2.1. 二进制数转换为十进制数
#+++++++++++++++++++++++++++++++++++
#<程序:2-to-10进制转换>
b=input("Please enter a binary number:")
d=0;
for i in range(0,len(b)):
if b[i] == '1':
weight = 2**(len(b)-i-1)
d = d+weight;
print(d)
#<程序:改进后的2-to-10进制转换>
b=input("Please enter a binary number:")
d=0; weight=2**(len(b)-1);
for i in range(0,len(b)):
if b[i] == '1':
d = d+weight;
weight=weight//2; #‘//’是整数除法
print(d)
#+++++++++++++++++++++++++++++++++++
#2.2.2. 十进制数转换为二进制数
#+++++++++++++++++++++++++++++++++++
#<程序:整数的10-to-2进制转换>
x= int(input("Please enter a decimal number:"))
r = 0;
Rs = [];
while(x != 0):
r = x% 2
x = x//2
Rs = [r]+Rs
for i in range(0,len(Rs)):
#从最高位到最低位依次输出;Rs[0]存的是最高位, Rs[len(Rs)-1]存的是最低位。
print(Rs[i],end='')
#<程序:整数的10-to-2进制转换-递归>
def convert(x): #把10进制数x转换为2进制数,并返回结果列表。
if x<2: return([x]) #x=0 或 1,所以返回x
r= x%2; #r 是2除x的余数
return(convert(x//2)+[r]) # 结果=[x//2的二进制,r]
num = int(input("Please enter a decimal number:"))
Rs= convert(num)
for i in range(0, len(Rs)):
print (Rs[i],end='')
#=====================================================================================
#===================================
#2.4. 一切都是逻辑(Logic)
#===================================
#+++++++++++++++++++++++++++++++++++
#2.4.3. 用逻辑做加法
#+++++++++++++++++++++++++++++++++++
#<程序: 全加器>
def FA(a,b,c): # Full adder
Carry = (a and b) or (b and c) or (a and c)
Sum = (a and b and c) or (a and (not b) and (not c)) \
or ((not a) and b and (not c)) or ((not a) and (not b) and c)
return Carry, Sum
#<程序:完整的加法器 Carry Ripple adder>
def add(x,y): # x, y are lists of True or False, c is True or False
# return carry and a list of x+y
while len(x) < len(y): x = [False]+x #前面补0
while len(y) < len(x): y = [False]+y #前面补0
L=[];Carry=False
for i in range(len(x)-1,-1,-1): #从最后一位一个个往前加
Carry,Sum=FA(x[i],y[i],Carry)
L=L+[Sum]
return (Carry, L)
#<程序:乘法器>
def multiplier(x,y): # 求x*y
S=[];
for i in range(len(y)-1,-1,-1):
if y[i] == True: #y[i]是 1,要将x加进到S
C, S=add(S,x)
if C==True: S=[C]+S
x=x+[False] #每一次x都要向左移一位,后面补0
return(S)
文章来源: fantianzuo.blog.csdn.net,作者:兔老大RabbitMQ,版权归原作者所有,如需转载,请联系作者。
原文链接:fantianzuo.blog.csdn.net/article/details/83025184
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